Optimal. Leaf size=83 \[ \frac{\tan ^{-1}\left (\frac{\sqrt [4]{b} \sqrt{c x}}{\sqrt{c} \sqrt [4]{a+b x^2}}\right )}{\sqrt [4]{b} \sqrt{c}}+\frac{\tanh ^{-1}\left (\frac{\sqrt [4]{b} \sqrt{c x}}{\sqrt{c} \sqrt [4]{a+b x^2}}\right )}{\sqrt [4]{b} \sqrt{c}} \]
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Rubi [A] time = 0.0502655, antiderivative size = 83, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 5, integrand size = 19, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.263, Rules used = {329, 240, 212, 208, 205} \[ \frac{\tan ^{-1}\left (\frac{\sqrt [4]{b} \sqrt{c x}}{\sqrt{c} \sqrt [4]{a+b x^2}}\right )}{\sqrt [4]{b} \sqrt{c}}+\frac{\tanh ^{-1}\left (\frac{\sqrt [4]{b} \sqrt{c x}}{\sqrt{c} \sqrt [4]{a+b x^2}}\right )}{\sqrt [4]{b} \sqrt{c}} \]
Antiderivative was successfully verified.
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Rule 329
Rule 240
Rule 212
Rule 208
Rule 205
Rubi steps
\begin{align*} \int \frac{1}{\sqrt{c x} \sqrt [4]{a+b x^2}} \, dx &=\frac{2 \operatorname{Subst}\left (\int \frac{1}{\sqrt [4]{a+\frac{b x^4}{c^2}}} \, dx,x,\sqrt{c x}\right )}{c}\\ &=\frac{2 \operatorname{Subst}\left (\int \frac{1}{1-\frac{b x^4}{c^2}} \, dx,x,\frac{\sqrt{c x}}{\sqrt [4]{a+b x^2}}\right )}{c}\\ &=\operatorname{Subst}\left (\int \frac{1}{c-\sqrt{b} x^2} \, dx,x,\frac{\sqrt{c x}}{\sqrt [4]{a+b x^2}}\right )+\operatorname{Subst}\left (\int \frac{1}{c+\sqrt{b} x^2} \, dx,x,\frac{\sqrt{c x}}{\sqrt [4]{a+b x^2}}\right )\\ &=\frac{\tan ^{-1}\left (\frac{\sqrt [4]{b} \sqrt{c x}}{\sqrt{c} \sqrt [4]{a+b x^2}}\right )}{\sqrt [4]{b} \sqrt{c}}+\frac{\tanh ^{-1}\left (\frac{\sqrt [4]{b} \sqrt{c x}}{\sqrt{c} \sqrt [4]{a+b x^2}}\right )}{\sqrt [4]{b} \sqrt{c}}\\ \end{align*}
Mathematica [A] time = 0.0113856, size = 65, normalized size = 0.78 \[ \frac{\sqrt{x} \left (\tan ^{-1}\left (\frac{\sqrt [4]{b} \sqrt{x}}{\sqrt [4]{a+b x^2}}\right )+\tanh ^{-1}\left (\frac{\sqrt [4]{b} \sqrt{x}}{\sqrt [4]{a+b x^2}}\right )\right )}{\sqrt [4]{b} \sqrt{c x}} \]
Antiderivative was successfully verified.
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Maple [F] time = 0.028, size = 0, normalized size = 0. \begin{align*} \int{{\frac{1}{\sqrt{cx}}}{\frac{1}{\sqrt [4]{b{x}^{2}+a}}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{{\left (b x^{2} + a\right )}^{\frac{1}{4}} \sqrt{c x}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 1.71301, size = 576, normalized size = 6.94 \begin{align*} -2 \, \left (\frac{1}{b c^{2}}\right )^{\frac{1}{4}} \arctan \left (-\frac{{\left (b x^{2} + a\right )}^{\frac{3}{4}} \sqrt{c x} b c \left (\frac{1}{b c^{2}}\right )^{\frac{3}{4}} -{\left (b^{2} c x^{2} + a b c\right )} \sqrt{\frac{\sqrt{b x^{2} + a} c x +{\left (b c^{2} x^{2} + a c^{2}\right )} \sqrt{\frac{1}{b c^{2}}}}{b x^{2} + a}} \left (\frac{1}{b c^{2}}\right )^{\frac{3}{4}}}{b x^{2} + a}\right ) + \frac{1}{2} \, \left (\frac{1}{b c^{2}}\right )^{\frac{1}{4}} \log \left (\frac{{\left (b x^{2} + a\right )}^{\frac{3}{4}} \sqrt{c x} +{\left (b c x^{2} + a c\right )} \left (\frac{1}{b c^{2}}\right )^{\frac{1}{4}}}{b x^{2} + a}\right ) - \frac{1}{2} \, \left (\frac{1}{b c^{2}}\right )^{\frac{1}{4}} \log \left (\frac{{\left (b x^{2} + a\right )}^{\frac{3}{4}} \sqrt{c x} -{\left (b c x^{2} + a c\right )} \left (\frac{1}{b c^{2}}\right )^{\frac{1}{4}}}{b x^{2} + a}\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [C] time = 1.7304, size = 44, normalized size = 0.53 \begin{align*} \frac{\sqrt{x} \Gamma \left (\frac{1}{4}\right ){{}_{2}F_{1}\left (\begin{matrix} \frac{1}{4}, \frac{1}{4} \\ \frac{5}{4} \end{matrix}\middle |{\frac{b x^{2} e^{i \pi }}{a}} \right )}}{2 \sqrt [4]{a} \sqrt{c} \Gamma \left (\frac{5}{4}\right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{{\left (b x^{2} + a\right )}^{\frac{1}{4}} \sqrt{c x}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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